275t-3t^2=0

Solution for 275t-3t^2=0 equation:

275t-3t^2=0

a = -3; b = 275; c = 0;
Δ = b2-4ac
Δ = 2752-4·(-3)·0
Δ = 75625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{75625}=275$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(275)-275}{2*-3}=\frac{-550}{-6}
=91+2/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(275)+275}{2*-3}=\frac{0}{-6}
=0
$